The Cit+ trait required the following mutation (technically it required more as it is known this one alone doesn’t suffice, but this will do for showing it is IC):
The citT transporter normally sits downstream of a promoter that is suppressed under aerobic conditions. That means when oxygen is present the cell doesn’t take in citrate.
During the course of the experiment the “segment amplified in Cit+” part was copied and inserted into the rnk gene. That means it was duplicated, and there is now a copy of the citT transporter sitting downstream of the rnk promoter, which is active when oxygen is present. For aerobic cit+ to work, the citT transporter must be present, and the promoter that is active under aerobic conditions must be present. Remover either one of these two parts and cit+ fails to function. Since removal of any one of these parts renders it nonfunctional, the trait is IC.
Btw even Behe agrees the trait is IC, he just responds by saying “simple” IC systems can evolve, and more complex ones can’t because the more parts it has the less probable the outcome. You know, his usual Texas Sharpshooter sh1te.
Do you not recall that I did this? You even agreed.
Okay here we go again:
Depending on what you think the ratio of beneficial to neutral/deleterious mutations are (and if you accept Sanford’s estimation that Lenski’s 1998 paper is the most reliable here), the ratio of beneficial to deleterious mutations in the LTEE is 1 in 106.
Since roughly 25 to 40 beneficial mutations (depending on which of the 12 replicate populations we pick) have by now fixed in each population, we can just calculate the total FI of 25 mutations, each with a probability of 10-6.
-log2((10-6)25) = 498.3 bits.
Wow you win the all time forum gold medal for ironic statement. I’ve literally done that calculation before to you. You semi-agreed (probably didn’t know how to respond because you stopped responding). So you really did repress the memory I see. Hilarious. No, actually, sad.